Determine the mass of the cargo to be sent on the raft, if during loading the raft displaced 2m3 of water.

When the body is in a liquid, we write the expression according to Newton’s second law, taking into account that the body is motionless:
m * g = Fa
A buoyant force acts on a body immersed in a liquid:
Fа = ρж * g * V, where ρж is the density of the liquid, g is the acceleration of free fall of a body raised above the Earth g = 9.8 m / s², V is the volume of the body.
The condition that the body does not sink:
m * g = ρl * g * V
Equilibrium before loading:
m1 * g = ρl * g * V1
After loading:
m2 * g = ρl * g * V2
Find the difference m2 * g-m1 * g:
m2 * g-m1 * g = ρl * g * V2-ρl * g * V1
Reducing g and replacing m2-m1 = Δm, V2-V1 = ΔV, we get:
Δm = ρl * ΔV
According to the reference book, the density of water ρzh = 1000 kg / m³.
Substitute the numerical values ​​and find the mass of the cargo:
Δm = ρl * ΔV = 1000 * 2 = 2000 kg.
Answer: a load of 2000 kg was loaded onto the raft.