Determine the mass of the ethanal solution with a mass fraction of 30% obtained

| March 5, 2021 | education

Determine the mass of the ethanal solution with a mass fraction of 30% obtained by the Kucherov reaction from 5.6 l of acetylene, if the reaction yield is 80%.

Let’s find the amount of the substance acetylene C2H2.

V = V: Vn.

V = 5.6: 22.4 L / mol = 0.25 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

C2H2 + HOH = CH3COH.

According to the reaction equation, 1 mol of С2Н2 is 1 mol of СН3СОН.

Substances are in quantitative ratios 1: 1.

Let us find the mass of CH3COH.

m = n × M,

M (CH3CHOH) = 44 g / mol.

m = 0.25 mol × 44 g / mol = 11 g (according to theory).

11 g – 100%,

X – 80%,

X = (11g × 80%): 100% = 8.8g.

W = m (substance): m (solution) × 100%,

m (solution) = (m (substance): W) × 100%,

m (solution) = (8.8 g: 30%) × 100% = 29.33%.

Answer: 29.33%.



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