Determine the mass of the formed salt if 200 g of a 30% acetic acid solution and sodium carbonate enter

| September 12, 2021 | education

Determine the mass of the formed salt if 200 g of a 30% acetic acid solution and sodium carbonate enter into the reaction, and the salt yield is 90% of the theoretically possible.

1.Let’s find the mass of CH3COOH in solution.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (200 g × 30%): 100% = 60 g.

2.Let’s find the amount of CH3COOH substance:

M (CH3COOH) = 60 g / mol.

n = 60 g: 60 g / mol = 1 mol.

Let’s find the quantitative ratios of substances.

2СН3СООН + Na2CO3 = 2СН3СОONa + CO2 ↑ + H2O.

For 2 mol of CH3COOH, there are 2 mol of CH3COOONa.

Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (CH3COONa) = n (CH3COOH) = 1 mol.

Let’s find the mass of СН3СОONa.

m = nM.

M (CH3COONa) = 82 g / mol.

m = 1 mol × 82 g / mol = 82 g.

82 g – 100%,

x g – 90%,

x = (82 g × 90%): 100% = 73.8 g.

Answer: 73.8 g.



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