Determine the mass of the mixture of calcium hydroxide and calcium carbonate, which contains 0.5 mol of each substance.

Given:
n (Ca (OH) 2) = 0.5 mol
n (CaCO3) = 0.5 mol
To find:
m s (Ca (OH) 2 + CaCO3)
Decision:
m (CaCO3) = n * M = 0.5 mol * 100 g / mol = 50 g
m (Ca (OH) 2) = n * M = 0.5 mol * 74 g / mol = 37 g
m (Ca (OH) 2 + CaCO3) = 50 g + 37 g = 87 g
Answer: 87 g



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