Determine the mass of the oxide, which was obtained by the interaction of 11.2 liters. oxygen with calcium.

Calcium enters into an oxidation reaction with oxygen. This reaction is described by the following equation:

Ca + ½ O2 = CaO;

When the reaction proceeds, one oxygen atom is attached to the calcium atom. During the reaction, one molecule of calcium oxide is synthesized.

Let’s determine the chemical (molar) amount of oxygen.

To do this, divide the available volume of gaseous oxygen by the volume of 1 mole of gas (22.4 liters).

N O2 = 11.2 / 22.4 = 0.5 mol;

When this reaction proceeds with oxygen, 2 times more calcium will react and, accordingly, 2 times more chemical amount of calcium oxide will be synthesized.

Let’s calculate its weight.

N CaO = 0.5 x 2 = 1 mol; M CaO = 40 +16 = 56 grams / mol; m CaO = 1 x 56 = 56 grams;