Determine the mass of the precipitate formed by the interaction of 1.42 g of sodium sulfate with barium nitrate.

Explanation of the solution to the problem: we compose the reaction equation, then we find the amount of sodium sulfate substance (we divide the mass of sodium sulfate by its molar mass), the amount of barium sulfate substance (precipitate) is equal to the amount of sodium sulfate substance, since according to the reaction their ratio is 1: 1, the latter step, we find the mass of barium sulfate by multiplying its amount of substance by its molar mass.