Determine the mass of the precipitate obtained by the reaction of sulfuric acid with a 20% solution

| January 6, 2021 | education

Determine the mass of the precipitate obtained by the reaction of sulfuric acid with a 20% solution of barium chloride weighing 200 grams.

Barium chloride reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Barium chloride reacts with sulfuric acid in equivalent molar amounts. This produces the same amount of insoluble salt.
Let’s calculate the chemical amount of barium chloride.
M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol; N BaCl2 = 200 x 0.2 / 208 = 0.1923 mol;
The same amount of barium sulfate will be synthesized.
Let’s find its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.1923 x 233 = 44.8 grams.



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