Determine the mass of the precipitate that is obtained by merging 5.8 g of sodium chloride with silver nitrate.

univerkov | January 17, 2021 | education

Given:
m (NaCl) = 5.8 g
Find: m (AgCl)
Decision:
NaCl + AgNO3 = AgCl + NaNO3
n (NaCl) = m / M = 5.8 g / 40 g / mol = 0.145 mol
n (NaCl): n (AgCl) = 1: 1
n (AgCl) = 0.145 mol
m (AgCl) = n * M = 0.145 mol * 143.5 g / mol = 20.81 g
Answer: 20.81 g

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