Determine the mass of the reaction product formed by the interaction of 12 grams of propanol

Determine the mass of the reaction product formed by the interaction of 12 grams of propanol with an excess of hydrogen chloride 18 g

To solve, we write down Data on the condition of the problem:
C3H7OH + HCl = C3H7Cl + H2O – exchange, chloropropane was formed;
Let’s make the calculations:
M (C3H7OH) = 60 g / mol;
M (C3H7Cl) = 78.5 g / mol.
Determine the amount of alcohol, if the mass is known:
Y (C3H7OH) = m / M = 12/60 = 0.2 mol;
Y (C3H7Cl) = 0.2 mol since the amount of substances is 1 mol.
Find the mass of the product:
m (C3H7Cl) = Y * M = 0.2 * 78.5 = 15.6 g
Answer: the mass of chloropropane is 15.6 g