Determine the mass of the salt and the amount of water substance obtained

Determine the mass of the salt and the amount of water substance obtained by the interaction of copper (II) hydroxide with 58.8 g of sulfuric acid.

Decision:
1) Cu (OH) ₂ + H₂SO₄ = CuSO₄ + 2H₂O
2) n (H₂SO₄) = 58.8 / 98 = 0.6 mol

3) n (salts) = n (H₂SO₄) = 2n (H₂O) = 0.6 mol

4) m (CuSO₄) = 0.6 * 160 = 96 g

5) n (H₂O) = 0.6 * 2 = 1.2 mol

Answer: 96 g, 1.2 mol