Determine the mass of the salt formed by merging 150 g of a 13% solution of barium nitrate with

Determine the mass of the salt formed by merging 150 g of a 13% solution of barium nitrate with sulfuric acid. (Reaction equation: barium nitrate + sulfuric acid)

Given:
m solution (Ba (NO3) 2) = 150 g
ω (Ba (NO3) 2) = 13%

To find:
m (salt) -?

1) Ba (NO3) 2 + H2SO4 => BaSO4 ↓ + 2HNO3;
2) m (Ba (NO3) 2) = ω * m solution / 100% = 13% * 150/100% = 19.5 g;
3) n (Ba (NO3) 2) = m / M = 19.5 / 261 = 0.1 mol;
4) n (BaSO4) = n (Ba (NO3) 2) = 0.1 mol;
5) m (BaSO4) = n * M = 0.1 * 233 = 23 g.

Answer: The mass of BaSO4 is 23 g.