Determine the mass of the salt formed by the interaction of iron 2 weighing 28 g with an excess of hydrochloric acid.

univerkov | January 17, 2021 | education

Given:
m (Fe) = 28 g
To find:
m (FeCl3)
Decision:
2Fe + 3Cl2 = 2FeCl3
n (Fe) = m / M = 28 g / 56 g / mol = 0.5 mol
n (Fe): n (FeCl3) = 2: 2
n (FeCl3) = 0.5 mol
m (FeCl3) = n * M = 0.5 mol * 162.5 g / mol = 81.25 g
Answer: 81.25 g

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