Determine the mass of the salt obtained by the interaction of 10 grams of silicon with 24%

| March 28, 2021 | education

Determine the mass of the salt obtained by the interaction of 10 grams of silicon with 24% impurities with an excess of sodium hydroxide. What is the volume of gas produced?

Let us find the mass of Si without impurities.

100% -24% = 76%.

10 g – 100%,

x – 76%,

x = (10 g × 76%): 100% = 7.6 g.

Let’s find the amount of substance Si:

M (Si) = 28 g / mol.

n = 7.6 g: 28 g / mol = 0.27 mol.

2.Let’s find the quantitative ratios of substances.

2NaOH + Si + H2O = Na2SiO3 + H2 ↑.

For 1 mole of Si, there is 1 mole of Na2SiO3.

Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (Si) = n (Na2SiO3) = 0.27 mol.

3.Let’s find the mass of Na2SiO3.

m = nM.

M (Na2SiO3) = 122 g / mol.

m = 0.27 mol × 122 g / mol = 32.94 g.

Let’s find the volume of hydrogen.

V = 0.27 × 22.4 L / mol = 6.048 L.

Answer: 32.94 g; 6,048 l.



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