Determine the mass of the salt obtained by the interaction of 12.6 g of acid nitrogen with barium hydroxide.

1. Let’s compose the equation of the proceeding reaction:

2HNO3 + Ba (OH) 2 = Ba (NO3) 2 + 2H2O;

2.Calculate the chemical amount of nitric acid:

n (HNO3) = m (HNO3): M (HNO3);

M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

n (HNO3) = 12.6: 63 = 0.2 mol;

3.determine the amount of barium nitrate obtained:

n (Ba (NO3) 2) = n (HNO3): 2 = 0.2: 2 = 0.1 mol;

4.calculate the mass of nitrate:

m (Ba (NO3) 2) = n (Ba (NO3) 2) * M (Ba (NO3) 2);

M (Ba (NO3) 2) = 137 + 2 * 14 + 6 * 16 = 261 g / mol;

m (Ba (NO3) 2) = 0.1 * 261 = 26.1 g.

Answer: 26.1 g.