Determine the mass of the salt obtained by the interaction of calcium oxide, weighing 63 grams, with 10% nitric acid solution.

Given:
m (HNO3) = 63 g
w (HNO3) = 10% = 0.1
To find:
m (Ca (NO3) 2)
Decision:
CaO + 2HNO3 = Ca (NO3) 2 + H2O
m in-va (HNO3) = m solution * w = 63 g * 0.1 = 6.3 g
n (HNO3) = m / M = 6.3 g / 63 g / mol = 0.1 mol
n (HNO3): n (Ca (NO3) 2) = 2: 1
n (Ca (NO3) 2) = 0.05 mol
m (Ca (NO3) 2) = n * M = 0.05 mol * 164 g / mol = 8.2 g
Answer: 8.2 g