Determine the mass of the salt that is formed by the interaction of 0.98 g of sulfuric

Determine the mass of the salt that is formed by the interaction of 0.98 g of sulfuric acid with sodium hydroxide, taken in an amount of 0.2 mol.

Let’s write down the solution:
H2SO4 + 2NaOH = Na2SO4 + 2H2O – ion exchange reaction, sodium sulfate obtained;
Let’s perform calculations using the formulas:
M (H2SO4) = 98 g / mol;
M (Na2SO4) = 118.9 g / mol.
We calculate the amount of H2SO4 mol by the formula:
Y (H2SO4) = m / M = 0.98 / 98 = 0.01 mol (deficient substance);
Y (NaOH) = 0.2 mol (substance in excess);
Calculations are made for the substance in deficiency.
Y (Na2SO4) = 0.01 mol, since the amount of sulfuric acid and salt is 1 mol.
Find the mass of Na2SO4 salt:
m (Na2SO4) = Y * M = 0.01 * 118.9 = 1.189 g.
Answer: the mass of sodium sulfate is 1.189 g.