Determine the mass of the salt that is formed by the interaction of calcium nitrate

Determine the mass of the salt that is formed by the interaction of calcium nitrate, weighing 200 g and omega = 70%, and phosphoric acid, the mass of which is 150 g.

1. First, let’s make the equation:
3Ca (NO3) 2 + 2 H3PO4 = Ca3 (PO4) 2 + 6 HNO3.
2. Let’s start counting, first, let’s calculate the mass:
m Ca (NO3) 2 = 200 * 0.7 = 140 (g).
3. We continue to count:
n Ca (NO3) 2 = 140/164 = 0.85 (mol).
n H3PO4 = 150/98 = 1.53 (mol).
4. Let’s make a semblance of proportion:
0.85 / 3 1.53 / 2

0.28 0.765
From it we see that in excess we get phosphoric acid.
5. Determine the mass of salt:
m Ca (NO3) 2 = 0.28 * 310 = 87 (g).
Answer: m = 87.

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