# Determine the mass of the salt that is formed by the interaction of calcium nitrate

August 31, 2021 | education

| **Determine the mass of the salt that is formed by the interaction of calcium nitrate, weighing 200 g and omega = 70%, and phosphoric acid, the mass of which is 150 g.**

1. First, let’s make the equation:

3Ca (NO3) 2 + 2 H3PO4 = Ca3 (PO4) 2 + 6 HNO3.

2. Let’s start counting, first, let’s calculate the mass:

m Ca (NO3) 2 = 200 * 0.7 = 140 (g).

3. We continue to count:

n Ca (NO3) 2 = 140/164 = 0.85 (mol).

n H3PO4 = 150/98 = 1.53 (mol).

4. Let’s make a semblance of proportion:

0.85 / 3 1.53 / 2

0.28 0.765

From it we see that in excess we get phosphoric acid.

5. Determine the mass of salt:

m Ca (NO3) 2 = 0.28 * 310 = 87 (g).

Answer: m = 87.

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