Determine the mass of the sediment that is formed by the action of silver nitrate Ag NO3 on 250 g.

univerkov | November 23, 2020 | education

Determine the mass of the sediment that is formed by the action of silver nitrate Ag NO3 on 250 g. 9% sodium phosphorus solution Na3PO4.

3AgNO3 + Na3PO4 = Ag3PO4 + 3NaNO3
m (na3po4) = 250 * 0.09 = 22.5
M (na3po4) = 23 * 3 + 31 + 16 * 4 = 464
n (na3po4) = 22.5 / 464 = 0.04
n (na3po4) = n (Ag3PO4) = 0.04
M (Ag3PO4) = 107 * 3 + 31 + 16 * 4 = 606
m (Ag3PO4) = 0.04 * 606 = 24.24

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