Determine the mass of the solution with a mass fraction of 5% sodium hydroxide required for interaction
Determine the mass of the solution with a mass fraction of 5% sodium hydroxide required for interaction with 150 g of a 15% solution of copper sulfate 2.
Find the mass of copper sulfate in solution.
The mass fraction of a substance is calculated by the formula:
W = m (substance): m (solution) × 100%,
m (substance) = (m (solution) × W): 100%,
m (substance) = (150 g × 15%): 100% = 22.5 g.
Let’s find the amount of copper sulfate substance by the formula:
n = m: M.
M (CuSO4) = 64 + 32 + 64 = 160 g / mol.
n = 22.5 g: 160 g / mol = 0.14 mol.
Let’s compose the reaction equation, find in what quantitative ratios the substances are.
CuSO4 + 2NaOH = Na2SO4 + Cu (OH) 2 ↓.
For 2 mol of sodium hydroxide there is 1 mol of copper sulfate. Substances are in quantitative ratios of 2: 1.
The amount of sodium hydroxide substance will be 2 times more than copper sulfate.
n (NaOH) = 2n (CuSO4) = 2 × 0.14 = 0.28 mol.
Find the mass of potassium carbonate.
m = n × M,
M (NaOH) = 40 g / mol.
m = 0.28 mol × 40 g / mol = 11.2 g.
The mass fraction of a substance is calculated by the formula:
W = m (substance): m (solution) × 100%,
m (solution) = (m (substance): W) × 100%,
m (solution) = (11.2 g: 5%) × 100% = 224 g.
Answer: 224 g.