Determine the mass of the solution with a mass fraction of sulfuric acid 5%

Determine the mass of the solution with a mass fraction of sulfuric acid 5%, which will be required for the reaction with 4 grams of copper oxide (||).

1.Let’s find the amount of copper oxide substance by the formula:

n = m: M.

M (CuO) = 64 + 16 = 80 g / mol.

n = 4 g: 80 g / mol = 0.05 mol.

2. Let’s compose the reaction equation, find in what quantitative ratios the substances are.

CuO + H2SO4 = CuSO4 + H2O.

1 mole of copper oxide accounts for 1 mole of sulfuric acid. Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (CuO) = n (H2SO4) = 0.05 mol.

3. Let’s find the mass of sulfuric acid.

m = n × M,

M (H2SO4) = 98 g / mol.

m = 0.05 mol × 98 g / mol = 4.9 g.

4. The mass fraction of a substance is calculated by the formula:

W = m (substance): m (solution) × 100%,

m (solution) = (m (substance): W) × 100%,

m (solution) = (4.9 g: 5%) × 100% = 98 g.

Answer: 98 g.



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