Determine the mass of the solution with a mass fraction of sulfuric acid 5%
Determine the mass of the solution with a mass fraction of sulfuric acid 5%, which will be required for the reaction with 4 grams of copper oxide (||).
1.Let’s find the amount of copper oxide substance by the formula:
n = m: M.
M (CuO) = 64 + 16 = 80 g / mol.
n = 4 g: 80 g / mol = 0.05 mol.
2. Let’s compose the reaction equation, find in what quantitative ratios the substances are.
CuO + H2SO4 = CuSO4 + H2O.
1 mole of copper oxide accounts for 1 mole of sulfuric acid. Substances are in quantitative ratios 1: 1.
The amount of substance will be equal.
n (CuO) = n (H2SO4) = 0.05 mol.
3. Let’s find the mass of sulfuric acid.
m = n × M,
M (H2SO4) = 98 g / mol.
m = 0.05 mol × 98 g / mol = 4.9 g.
4. The mass fraction of a substance is calculated by the formula:
W = m (substance): m (solution) × 100%,
m (solution) = (m (substance): W) × 100%,
m (solution) = (4.9 g: 5%) × 100% = 98 g.
Answer: 98 g.