Determine the mass of water that is formed during the complete combustion of 44.8 liters of ethylene

1. We write down the reaction equation for the combustion of ethylene:

C2H4 + 3O2 → 2CO2 + 2H2O;

2.Calculate the chemical amount of ethylene:

n (C2H4) = V (C2H4): Vm = 44.8: 22.4 = 2 mol;

3. Determine the amount of water generated:

n (H2O) = n (C2H4) * 2 = 2 * 2 = 4 mol;

4.find the mass of water:

m (H2O) = n (H2O) * M (H2O) = 4 * 18 = 72 g.

Answer: 72 g.