Determine the mass of zinc, which is required to react with HCI, if 5.6 liters of H.

1. We make the equation:

Zn + 2HCl → ZnCl2 + H2 ↑

2. Find the amount of hydrogen:

n (H2) = V (H2): Vm = 5.6 L: 22.4 L / mol = 0.25 mol.

3. The coefficients in the reaction equation show the ratio of the amount of zinc to the amount of hydrogen:

n (Zn): n (H2) = 1: 1.

This means that the amount of zinc n (Zn) is 1 mol.

4. The molar mass of zinc M (Zn) numerically coincides with its relative atomic mass and is equal to 65 g / mol.

5. Zinc mass:

m (Zn) = n (Zn) × M (Zn) = 1 mol × 65 g / mol = 65 g.