Determine the masses of 10% and 30% solutions of the same substance required to prepare 300 g of a 15% solution?

univerkov | December 10, 2020 | education

let x be the mass of the first solution
y = mass of the second
300 g of 15% solution contains 45 g of pure substance
0.1x + 0.3y = 45
x + y = 300
x = 300-y – plug this into the first equation
0.1 (300-y) + 0.3y = 45
30-0.1y + 0.3y = 45
0.2y = 15
y = 75 x = 225
answer
weight of the first 75, the second – 225

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