Determine the maximum current in a coil with an inductance of 3 H when connecting

Determine the maximum current in a coil with an inductance of 3 H when connecting a capacitor with a capacity of 48 μF, charged to a voltage of 200 V, to it.

Initial data: L (coil inductance) = 3 H; C (capacitance of the capacitor connected to the coil) = 48 μF (48 * 10 ^ -6 F); U (voltage to which the capacitor was charged) = 200 V.

The maximum current in the coil can be determined from the formulas for calculating the energies of a charged capacitor and a coil with a current: W = 0.5 * L * I ^ 2 = 0.5 * C * U ^ 2, whence I = √ (C * U ^ 2 / L).

Let’s make a calculation: I = √ (48 * 10-6 * 200 ^ 2/3) = 0.8 A.

Answer: The maximum current in the coil is 0.8 A.