Determine the mechanical work performed by a tractor that plowed a plot with an area of 1 hectare if the plow width is 1.2 m and the traction force = 15000 (Newton)
Data: S (plowed area) = 1 ha = 10 ^ 4 m2; B (plow width) = 1.2 m; F (tractor pulling force) = 15 * 10 ^ 3 N.
Horse mechanical work: A = F * L = F * S / B = 15 * 10 ^ 3 * 10 ^ 4 / 1.2 = 125 * 10 ^ 6 J.
Answer: The mechanical work (minimum) of the tractor when plowing the area is 125 MJ.
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