Determine the minimum vehicle speed when braking at a distance of 25 meters (coefficient of friction – 0.8).

V ^ 2 = 2aS Ftr = ma = kmg-> a = kg V ^ 2 = 2kgS V = √ (2kgS)
Solution: V = √ (2 * 0.8 * 10 * 25) = 20m / s = 72 kilometers per hour
Answer: 72 kilometers per hour.



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