Determine the module EMF of self-induction, which is excited in the electromagnet winding with an inductiveness

Determine the module EMF of self-induction, which is excited in the electromagnet winding with an inductiveness of 0.6 H when the current in it changes by 6 A in 0.036 s.

Initial data: L (inductance of the electromagnet winding) = 0.6 H; ΔI (change in current in the winding) = 6 A; Δt (duration of current change) = 0.036 s.

The EMF module of self-induction in the electromagnet winding is determined by the formula: ε = | L * ΔI / Δt |.

Calculation: ε = 0.6 * 6 / 0.036 = 100 V.

Answer: A self-induction EMF of 100 V is excited in the electromagnet winding.



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