Determine the modulus of force F of two point charges q1 = 6.0 μC and q2 = -12 μC if the distance between them is r = 10 μC.

According to Coulomb’s law:
F = k * | q1 | * | q2 | / r², where k is the proportionality coefficient (k = 9 * 109 N * m² / Kl²), q1 is the value of the first charge (q1 = 6 μC = 6 * 10-6 C), q2 is the value of the second charge (q2 = -12 μC = -12 * 10-6 C), r is the distance between charges (r = 10 microns = 10 * 10-6 m).
Let’s calculate the strength of the Coulomb interaction:
F = k * | q1 | * | q2 | / r² = 9 * 109 * 6 * 10-6 * 12 * 10-6 / (10 * 10-6) 2 = 6,480,000,000 N = 6.48 HN.
Answer: The modulus of force of two point charges is 6.48 GN.