Determine the modulus of the electromagnet with self-induction, which is excited in the electromagnet

Determine the modulus of the electromagnet with self-induction, which is excited in the electromagnet winding with an inductance of 0.5 H with a uniform change in the current strength by 6 A for every 0.03 s

The EMF of self-induction is directly proportional to the inductance of the coil and the change in the current in this coil and is inversely proportional to the time interval during which the change in current occurred.

Ес = -L * ΔI / Δt.

Ес – EMF of self-induction.

L = 0.5 [H] – coil inductance.

ΔI = 6 [A] – change in the strength of the current in the coil.

Δt = 0.03 [s] – time interval.

Accordingly, the EMF module of self-induction is equal to:

| EU | = | -L * ΔI / Δt | = L * ΔI / Δt (where ΔI is a positive number).

| EU | = 0.5 [H] * 6 [A] / 0.03 [s] = 100 [B].