Determine the molar masses of equivalents of the following compounds: HBr, Mg (OH) 2, NaHCO3.

univerkov | December 11, 2020 | education

M (HBr) = 1 + 79.9 = 80.9 (g / mol)
M (Mg (OH) 2) = 24.3 + 2 * 17 = 24.3 + 34 = 58.3 (g / mol)
M (NaHCO3) = 23 + 1 + 12 + 3 * 16 = 36 + 48 = 84 (g / mol)
Answer:
M (HBr) = 80.9 (g / mol);
M (Mg (OH) 2) = 58.3 (g / mol);
M (NaHCO3) = 84 (g / mol)

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