Determine the molecular formula of a cycloalkane if its vapor density with respect to nitrogen is 2.5.

Let the molecular formula of the unknown cycloalkane be: CnH2n.

Let’s determine the molecular weight of CnH2n:

M (CnH2n) = M (N2) * DN2 (CnH2n) = 28 * 2.5 = 70 (amu).

Let’s compose and solve the equation:

12 * n + 1 * 2n = 70,

14n = 70,

n = 5, whence the formula of cycloalkane: C5H10 (which corresponds to cyclopentane).

Answer: C5H10.



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