Determine the molecular formula of nitrate in which 24.39 hundredths of a percent calcium 17.7% nitrogen 58.54% oxygen.

univerkov | December 3, 2020 | education

Let m (compounds) = 100 g
then
m (Ca) = 24.39 g n (Ca) = 24.39 \ 40 = 0.6 mol
m (N) = 17.7 g n (N) = 17.7 \ 14 = 1.26 mol
m (O) = 58.54 g n (O) = 58.54 \ 16 = 3.66 mol
n (Ca): n (N): n (O) = 0.6: 1.26: 3.66 = 1: 2: 6
Answer: Ca (NO3) 2

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