Determine the molecular formula of the hydrocarbon if the mass fraction of carbon is 82.76%, and the relative density
| December 16, 2020 | education
Determine the molecular formula of the hydrocarbon if the mass fraction of carbon is 82.76%, and the relative density for oxygen is 1.8125. Draw up the structural and molecular formula and name the substance.
M (ugv) = 32 * 1.8125 = 58 g / mol
let it be alkane
C (n) H (2n + 2)
12n / 14n + 2 = 0.8276
14n + 2 = 58
n = 4 – agreed
C4H10
CH3-CH2-CH2-CH3 – butane and its isomer 2-methylpropane
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