Determine the momentum of a pellet at the moment of departure from a hunting rifle, if its initial speed is 200 m / s, and its mass is 5 g, how does the momentum of a pellet change if its mass is 2 times less, and its speed is 1.5 times greater
Given: V0 (initial velocity of the pellet) = 200 m / s; m0 (initial mass of the pellet) = 5 g (in SI m0 = 5 * 10-3 kg).
1) Determine the initial impulse of the pellet under consideration: P0 = m * V = 200 * 5 * 10-3 = 1 kg * m / s.
2) Determine the momentum of the pellet after changing its parameters (m = 0.5m0 and V = 1.5V0): k = P / P0 = m * V / (m0 * V0) = 0.5m0 * 1.5V0 / (m0 * V0) = 0.75 p.
Answer: The momentum of the pellet under consideration is 1 kg * m / s; after changing the physical parameters, the momentum of the pellet will decrease by 0.75 times.
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