Determine the number of atoms in iridium with a volume of 0.5m3. The molar mass of iridium

Determine the number of atoms in iridium with a volume of 0.5m3. The molar mass of iridium is 0.1922 m / mol, density is 22650m / m3.

Initial data: V (volume of iridium taken) = 0.5 m3.

Reference values: M (molar mass of iridium) = 0.1922 kg / mol; ρ (density of iridium) = 22650 kg / m3; Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1.

1) Determine the mass of the taken iridium: m = ρ * V = 22650 * 0.5 = 11325 kg.

2) Let’s calculate the number of atoms in iridium: N / Na = m / M, whence N = m * Na / M = 11325 * 6.02 * 10 ^ 23 / 0.1922 ≈ 354.7 * 10 ^ 26 atoms.

Answer: 0.5 m3 of iridium contains 354.7 * 10 ^ 26 atoms.