Determine the number of double and triple bonds in the molecule and the length of the DNA chain section

| April 5, 2021 | education

Determine the number of double and triple bonds in the molecule and the length of the DNA chain section, which contains 12 adenyl and 20 guanyl nucleotides (in two DNA strands). The distance between nucleotides is taken equal to 0.34 nm.

Given a DNA section, based on the principle of complementarity A – T, G – C, we will determine the number of nucleotides in the chain.

A = T, A = 12, so T = 12

G = C, G = 20, C = 20

20 + 20 + 12 + 12 = 64 (total nucleotides in the double strand of DNA).

The distance between nucleotides is 0.34 nm, the length of a DNA chain segment is equal to the length of any of its chains.

64 * 0.34 = 21.76 nm (DNA length)

Double bonds are formed between adenine and thymine, which means there are 12 double bonds, triple bonds form guanine and cytosine, which means there are 20 triple bonds in total.



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