Determine the number of moles of air in a room with a volume of 5 * 6 * 3m3 at a temperature of 27 .

Determine the number of moles of air in a room with a volume of 5 * 6 * 3m3 at a temperature of 27 and a pressure of 19 ^ 5 PA.

Let’s find the volume of the room: V = 5 * 6 * 3 = 90 m³.

We translate the temperature into SI: T = t + 273 = 27 + 273 = 300 K.

The pressure appears to be in error. Should be 10 ^ 5 Pa.

Let’s use the Mendeleev-Clapeyron equation:

p * V = ν * R * T,

whence the number of moles of air is

ν = p * V / (R * T);

ν = 10 ^ 5 * 90 / (8.31 * 300) = 3610 mol.