Determine the number of protons, neutrons and electrons orbiting the nucleus of element 13 and name this element.

Chemical element – aluminum (Al)

Is in the third period (small), in the third group (main subgroup)

Serial number – 13

The relative atomic mass is 27

Atom structure:

The number of electrons is 13, the number of protons is 13, in order to calculate the number of neutrons, it is necessary to subtract the ordinal number from the relative atomic mass, we get: 27 – 13 = 14

+ 13Al) 2) 8) 3 1s2 2s2 2p6 3s2 3p1

At the last energy level there is 1 electron, the level is not complete.

The valence of aluminum is constant and equal to III

Superior oxide formula: Al2O3, the character of the oxide is amphoteric.

Base formula: Al (OH) 3

It has no volatile hydrogen compound.