Determine the period and frequency of oscillations of the spring pendulum, if its mass is 100g

| August 2, 2021 | education

Determine the period and frequency of oscillations of the spring pendulum, if its mass is 100g, and the spring rate is 400N / m.

Determine the period and frequency of oscillations of the spring pendulum, if its mass is 100g, and the spring rate is 400N / m

k = 400 N / m.

m = 0.1 kg.

T -?

v -?

The oscillation period T is called the time of one complete oscillation: T = t / N, where t is the oscillation time, N is the number of oscillations.

For a spring pendulum, the period is determined by the formula: T = 2 * P * √ (m / k), where P is the number pi, m is the mass of the load, k is the stiffness of the spring.

T = 2 * 3.14 * √ (0.1 kg / 400 N / m) = 0.1 s.

The frequency of oscillations v is the number of oscillations per unit of time: v = N / t = 1 / T.

v = 1 / 0.1 s = 10 s ^ -1 = 10 Hz.

Answer: the oscillation period is T = 0.1 s, the oscillation frequency is v = 10 Hz.



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