Determine the period and frequency of oscillations of the spring pendulum if the mass of the load
Determine the period and frequency of oscillations of the spring pendulum if the mass of the load suspended on a spring with a stiffness of 25N / M is equal to 250 grams.
Determine the period and frequency of oscillation of the spring pendulum, if the mass of the load suspended on a spring with a stiffness of 25N / M is equal to 250 grams.
k = 25 N / m.
m = 250 g = 0.25 kg.
T -?
v -?
The oscillation period T is called the time of one complete oscillation: T = t / N, where t is the oscillation time, N is the number of oscillations.
For a spring pendulum, the period is determined by the formula: T = 2 * P * √ (m / k), where P is the number pi, m is the mass of the load, k is the stiffness of the spring.
T = 2 * 3.14 * √ (0.25 kg / 25 N / m) = 0.628 s.
The frequency of oscillations v is the number of oscillations per unit of time: v = N / t = 1 / T.
v = 1 / 0.628 s = 1.6 Hz.
Answer: the oscillation period is T = 0.628 s, the oscillation frequency is v = 1.6 Hz.