Determine the period of oscillation of a spring pendulum weighing 40 g, if the spring rate is 2 N / m.
| February 24, 2021 | education
Given: m (the mass of the taken spring pendulum) = 40 g (0.04 kg); k (value of the spring stiffness of the pendulum) = 2 N / m.
The oscillation period of the spring pendulum taken can be calculated by the formula: T = 2Π * √ (m / k).
Calculation: T = 2 * 3.14 * √ (0.04 / 2) = 6.28 * √0.02 = 0.888 s.
Answer: The oscillation period of the taken spring pendulum is 0.888 s.
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