Determine the period of vibration of a body weighing 10 kg. Suspended from a spring with a rigidity of 1000N \ m.

The oscillation period of the spring pendulum is found by the formula
T = 2п√ (m / k)
Now we just substitute the values
T = 2 * 3.14√ (10/1000) = 0.628 (s)
Answer: T = 0.628 (s)



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