Determine the pH of 0.02N dichromic acid solution if the degree of dissociation is 50%.

SN = 0.02 N.

Determine the pH of the dichromic acid solution. We write down the solution.

For this we use the following formula. We get the following.

PH = – lg (H)

(H) = √K * cm

Since Cm = CH = 0.02 mol / l,

The normal concentration is equal to the molar concentration.

a K = * Cm = * Cn, then (H) = √ * Cn = * Cn = 0.5 * 0.02 = 0.01 pH = -log 0.01 = 2

The result is an answer equal to 2.