Determine the possible phenotypes of children if the mother and father have wavy hair, the mother has brown

Determine the possible phenotypes of children if the mother and father have wavy hair, the mother has brown eyes, and the father has blue. (the gene for course hair dominates the gene for straight hair; the gene for brown eyes dominates over the gene for blue eyes)

Let’s designate the gene that determines the development of curly hair as “A”, then the gene for straight hair will be “a”. Wavy hair is the result of the phenomenon of the so-called incomplete dominance, when the combination of both genes in the genotype – both dominant and recessive – causes the development of a new, intermediate trait. Such a sign in this task is wavy hair – Aa.

Let’s designate the gene that causes brown eyes as “B”, then the gene for blue eyes will be “b”.

The father has blue eyes and wavy hair – Aabb, he produces spermatozoa Ab and ab.

The mother has brown eyes and wavy hair – her genotype is either AaBB or AaBb. Let’s consider both options.

Mother AaBB, produces eggs AB and AB. The offspring of such a pair may include the following options: brown-eyed children with curly hair (AABb), brown-eyed children with wavy hair (AaBb), brown-eyed children with straight hair (aaBb).

Mother AaBb, produces eggs AB, ab, aB and Ab. Possible offspring of this pair: curly brown-eyed children (AABb, AAbb), blue-eyed children with wavy hair (Aabb), brown-eyed children with wavy hair (AaBb), blue-eyed children with straight hair (aabbb), brown-eyed children with straight hair (aaBb).