Determine the potential difference across the plates of a capacitor with a capacity of 200pF

Determine the potential difference across the plates of a capacitor with a capacity of 200pF, if the plates were told a charge of 5μC

These tasks: C (the capacity of the capacitor taken) = 200 pF (200 * 10-12 F); q (charge imparted to the plates) = 5 μC (5 * 10-6 C).

The required potential difference on the plates of the capacitor taken is determined by the formula: φ1 – φ2 = q / C.

Let’s calculate: φ1 – φ2 = 5 * 10-6 / (200 * 10-12) = 25,000 V (25 kV).

Answer: The required potential difference on the plates of the capacitor taken is 25 kV.