Determine the potential difference at the ends of a 5 Ohm conductor if, after a minute, a charge of 2.88 kC passes through its cross section.
Initial data: R (conductor resistance) = 5 Ohm; t (duration of current passage) = 1 min (60 s); q (passed charge) = 2.88 kC (2800 C).
The potential difference at the ends of the taken conductor is determined by the formula: φ1 – φ2 = I * R = (q / t) * R.
Calculation: φ1 – φ2 = (2880/60) * 5 = 240 V.
Answer: At the ends of the conductor, the potential difference is 240 V.
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