Determine the potential energy of a spring compressed by 30 cm with a force of 2600.
| May 28, 2021 | education
Initial data: Δх (compression (deformation value) of the spring) = 30 cm = 0.3 m; F (force acting on the spring) = 2600 N.
The potential energy of the spring in question is determined by the formula: En = 0.5 * k * Δx2 = 0.5 * (F / Δx) * Δx2 = 0.5 * F * Δx.
Calculation: Ep = 0.5 * 2600 * 0.3 = 390 J.
Answer: When compressed, the spring acquired a potential energy of 390 J.
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