Determine the power developed by the tractor engine, which, at a travel speed of 5 m / s

Determine the power developed by the tractor engine, which, at a travel speed of 5 m / s, overcomes a resistance force of 40 kN.

Initial data: V (speed of the considered tractor) = 5 m / s; F (resistance force that the tractor overcomes) = 40 kN (40 * 10 ^ 3 N).

The power that the engine of the tractor under consideration should develop is calculated by the formula: N = F * V.

Let’s make a calculation: N = 40 * 10 ^ 3 * 5 = 200 * 10 ^ 3 W (200 kW).

Answer: The engine of the tractor in question has a power of 200 kW.