Determine the power: electric. light bulbs whose resistance is 200 Ohm, the voltage in the network is 220 V

Determine the power: electric. light bulbs whose resistance is 200 Ohm, the voltage in the network is 220 V, the soldering iron has a resistance of 100 Ohms, the voltage in the network is 110 V, the spiral resistance of which is 300 Ohms, the voltage in the network is 380 V, the vacuum cleaner’s resistance is 150 Ohms, the voltage in the network is 220 V.

The power can be found by the formula: P = I * U, and the current strength is found by Ohm’s law I = U / R.

1) For an electric lamp: I = 220V / 200Ω = 1.1A; P = 1.1A * 220V = 242W.

2) For a soldering iron: I = 110V / 100Ω = 1.1A; P = 1.1A * 110V = 121W.

3) For the coil: I = 380V / 300Ω = 1.27A; P = 1.27A * 380V = 481W.

4) For a vacuum cleaner: I = 220V / 150Ω = 1.47A; P = 1.47A * 220V = 322.7W.



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