Determine the power of the engine lifting 300 kg by 12 m in 30 seconds.
| September 7, 2021 | education
Task data: m (cargo weight) = 300 kg; h (lifting height) = 12 m; t (duration of engine operation) = 30 s.
Reference values: g (acceleration due to gravity) ≈ 10 m / s2.
The engine power is determined by the formula: N = ΔEp / t = m * g * h / t.
Calculation: N = 300 * 10 * 12/30 = 1200 W or 1.2 kW.
Answer: The engine has a power of 1.2 kW.
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